(64x^8/27y^(-4))^(-3/4)

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Solution for (64x^8/27y^(-4))^(-3/4) equation: 


D( x )

((64*x^8)/27)*y^-4 < 0

((64*x^8)/27)*y^-4 = 0

((64*x^8)/27)*y^-4 < 0

((64*x^8)/27)*y^-4 < 0

((64*x^8)/27)*y^-4 = 0

64/27*x^8*y^-4 = 0 // : 64/27*y^-4

x^8 = 0

x = 0

x < 0

(-oo:0)(0:+oo)x-+

((64*x^8)/27)*y^-4 = 0

((64*x^8)/27)*y^-4 = 0

64/27*x^8*y^-4 = 0 // : 64/27*y^-4

x^8 = 0

x = 0

x in (0:+oo)

(((64*x^8)/27)*y^-4)^(-3/4) = 0

(64/27)^(-3/4)*x^-6*y^3 = 0 // : (64/27)^(-3/4)*y^3

x^-6 = 0

x naleu017Cy do O

x belongs to the empty set

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